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/sci/ - Science & Math

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>> No.4705379 [View]

>>4705357
waaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaat?

>> No.4705369 [View]

>>4705324
???

3^x + 9 • 3^x = 10 • 3^x

3^x + 9 = 10

10 - 9 = 3^x

3^x = 1

wãt

>> No.3938503 [View]

wut

>> No.3844727 [View]

>>3844721

>darwin
>feynman
>hawking

>not science


wut

>> No.3688666 [View]
File: 14 KB, 200x200, 525062a8eea28075c02ec9ed12168ad3.jpg [View same] [iqdb] [saucenao] [google]
[ERROR]

Does /sci/ know of any good math programs for Windows, besides MathCad.

>> No.3012806 [View]

its threads like these that require facebook-stype 'like' buttons

>> No.2556791 [View]

>>2556751
Not OP. Note how I made my name wut.

>>2556741
>>2556743
Alright. I guess i^2 = -1
Because the rules of mathematics in this world don't apply to this statement. I won't argue it, the crazy theoretical physicists and mathematicians sure don't question it.

>> No.2556719 [View]
File: 4 KB, 126x115, 1285394969149s.jpg [View same] [iqdb] [saucenao] [google]
2556719

So if the imaginary number i = the square root of -1

How the hell does i^2 = -1?
If you were to raise both sides of i = square root of -1 you could just remove the radical bracket, but the process behind it would be to multiply radical -1 times radical -1. That would = radical 1
radical 1 = 1
So how does i^2 = -1?

Picture related. My face trying to think about this.

>> No.1672482 [View]
File: 99 KB, 469x600, 1283115158904.jpg [View same] [iqdb] [saucenao] [google]
1672482

Some troll/retard was using the eye as an excuse for creationism. I forgot the title of the video I was looking for, but found it.

http://www.thatvideosite.com/video/david_attenborough_on_the_evolution_of_the_eye

Discuss...

>> No.1657906 [View]
File: 1.13 MB, 2048x1536, IMG_0098.jpg [View same] [iqdb] [saucenao] [google]
1657906

But at least we have nice beaches near campus..

>> No.1657904 [View]
File: 1.19 MB, 2048x1536, IMG_0097.jpg [View same] [iqdb] [saucenao] [google]
1657904

Same boat as OP. Community college... fuck yea. >_> Can't wait to finish up with my A.A...

>> No.1641258 [View]

>>1641186
wut

>> No.1330552 [View]
File: 50 KB, 744x567, 1272323025498.jpg [View same] [iqdb] [saucenao] [google]
1330552

http://www.youtube.com/watch?v=6c2mjq2n3Yg
Let us praise him for his genius.

>> No.963314 [View]

bump again

>> No.963266 [View]

>>963239
the main problem is that we want to go under the resolution of the spectrometer, hence the addition of the FP. The spectrometer has a resolution of ~60µeV and the FP has a FSR of ~80 µeV. The main problem is that i can't know the distance between the mirrors with enough precision the know the order of interference in lambda. Using two wavelengths, i can find the distance, but i will be lacking some precision in mesurements.

>> No.963218 [View]

bump

>> No.963181 [View]
File: 43 KB, 560x420, fabrypeorot.jpg [View same] [iqdb] [saucenao] [google]
963181

If i want to make a mesurement with a fabry-perot interferometer, how would i go? It's linked with a spectrometer after so i cant mesure the rings. I have no effective way of mesuring the distance between mirrors, but i have two wavelengths running. (FSR > spectrometer resolution). I am interested in obtaining the source function. If i can obtain the transmission function as wavelength i cn deconvolve, but i would need distance. halp

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