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/sci/ - Science & Math

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>> No.6118166 [View]
File: 42 KB, 604x426, tyson wrestling.jpg [View same] [iqdb] [saucenao] [google]
6118166

http://www.youtube.com/watch?v=kBTd9--9VMI

welp, discuss.

pic semi-related

>> No.6117166 [View]

>>6117124

it juz maeks u ask urself... what the bleep do we no!!!!

>.<

>> No.6115512 [View]

>>6115509

i know the feel every 3 weeks m8

>> No.6115502 [View]
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6115502

>i at least got an 83 on that chem exam
>78
>i was the only one in the class that got the long math problem right
>mfw my class doesn't know how to use the quadratic formula apparently

>> No.6103797 [View]
File: 57 KB, 500x667, fedorad&#039;d gentleman.jpg [View same] [iqdb] [saucenao] [google]
6103797

>>6103793

fuck totally forgot about applying the coefficients to the X value in the change row.

thx m8

>> No.6103755 [View]

sci pls

>> No.6103720 [DELETED]  [View]
File: 58 KB, 969x670, im retarded.jpg [View same] [iqdb] [saucenao] [google]
6103720

What is the logic that I apply in finding the molarity for the change section for the two reactants?

I can solve by deductive reasoning since it's multiple choice, but on the test it won't be.


How do i find the change value for the reactants when only giving the molarity in equilibrium of the product?


pic very related. pls don't judge me


for the change row (C); A = -.20M, B = -.40M


I was thinking of dividing the coefficients of the reactant by the product.

Like for B i'd do (2/3)x(.6), it works for B but if i were to apply that to A it'd give me .133

>> No.6099069 [View]

>>6099061


should be. It takes awhile to do so i plan to bring a chair, lunch box, coffee and a book. shud b fun

>> No.6099051 [View]

>>6098919

>tfw sometime in the winter i'm going to drive out to the beach around 1 AM and attempt to make my first star trail photo
>tfw i know i'm going to fuck it up somehow

>> No.6095311 [View]
File: 8 KB, 251x247, 1310147513811.jpg [View same] [iqdb] [saucenao] [google]
6095311

>>6095186

>inb4 100 replies and month long arguments
>month long arguments

it's funny because it's entirely plausible on this board

>> No.6090043 [View]

>watch a bunch of his videos
>end up seeing him live
>it's everything from his videos with a few extra powerpoint slides
>only the retards get the mic to ask questions during the Q&A
>listen to him explain what a quasar is to some dude who's going to forget in two days

but neil himself is kewl

>> No.6077432 [View]
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6077432

>>6076806

sombrero all day

>> No.6075346 [View]
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6075346

>>6075319

christ dude and i thought mine were bad

>> No.6074021 [DELETED]  [View]
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6074021

Was finding equilibrium constant in chem today and we were applying the small x approximation.

Is this method used commonly in other fields? Was kind of surprised we'd all of a sudden be applying approximations rather than getting super anal and finding the absolute answer.

I can't imagine this being acceptable in a lab

>> No.6062285 [View]

>>6062281

u must b engineering student

>> No.6062278 [View]

>>6062253

psh it's only a speech class m8

>> No.6062248 [View]
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6062248

>in speech class today
>we're working on our outline
>i'm getting my sources together
>most of them being from nasa.gov and noaa.gov (doing speech on climate change)
>go to sites
>mfw
>tell professor
>she laughs and offers to move my due date back

thx congress ;)

>> No.6058231 [View]
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6058231

how exactly do i solve part (c) of 34?

a.) = 2.48x10^6 s

b.) = 41 days

pls /sci/ ;_;

>> No.6057114 [View]
File: 29 KB, 1427x964, u wot.png [View same] [iqdb] [saucenao] [google]
6057114

ok wut

>> No.6048367 [View]

is hypothesizing FTL mostly just wishful thinking?

>> No.6044894 [View]

>>6044882

yeah my main focus was the energy from the stirring + absorption of heat through the metal spoon compared to the convection from stirring.

wasn't sure which would dominate each other

>> No.6044817 [View]
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6044817

just a random thermodynamics question i was thinking about the other day.


Would stirring sugar into hot coffee cool the coffee or heat it up?

the enthalpy of the sugar mixing with the coffee being negligible. just focused on the energy from stirring. I guess the metal spoon absorbing heat will be negligible also

>does the energy from stirring coffee heat or cool the coffee

room temp being like 25C @ 1atm

>> No.6035600 [View]

if i've never heard of this guy then is he really a threat.

>> No.6034856 [View]

http://www.youtube.com/watch?v=7FnXgprKgSE

does planet earth count too?

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