/lit/ - Literature

[Anonymous No.2742500]

Book Titles Thread

I wrote a novel and I think the title kind of sucks. What kind of titles do you think are catchy? Short ones with two words?
XX?
X and the X?
etc...

What are some of your favorite book titles? Try to be unbiased whether the book was good. Just catchy titles.

[Anonymous No.2742504]

Distance light has traveled from t_{emitted} to t_{now}.

Working in the context in which the spatial part of spacetime is flat. The metric can be written:

ds^{2}=c^{2}dt^{2}-a^{2}(t)dx^{2}


Where a(t) is the scale factor of the Universe at time t, and c is the speed of light.

The special characteristic of the trajectory followed by light is that ds^{2}=0 (the speed of light is ALWAYS the speed of light) along the path, which implies that \left | dx \right |=\frac{cdt}{a(t)}, or, for what I'm workin' with here (a finite time interval) \int \left | dx \right |=\int_{t_{emitted}}^{t_{now}}\frac{cdt}{a(t)}

The left side of the above equation gives the distance light travels across the distance in STATIC space between the time of emission, and now. Obviously, to make this fit with the current view of the expanding Universe you gotta rescale the formula. Doing this gives,

a(t_{now})\int_{t_{emitted}}^{t_{now}}\frac{cdt}{a(t)}


When calculating the distance traveled in an expanding Universe we see that each segment of the lights trajectory is multiplied by the factor \frac{a(t_{now})}{a(t)}, which is the amount by which that segment has stretched, since the moment light traversed it, until today.

So, yeah, you can calculate distance.

[Anonymous No.2742505]

Do what everyone else does:

1. Read every Shakespeare play
2. Find a line that sorta kinda talks about what your book is about.
3. Use that.

[Anonymous No.2742506]

Depends what the book is about and prospective audience.

[Anonymous No.2742507]

>>2742504

Also, for clarification, I'm using comoving coordinates here.

[Anonymous No.2742508]

trimalchio in west egg

[Anonymous No.2742509]

Distance light has traveled from t_{emitted} to t_{now}.

Working in the context in which the spatial part of spacetime is flat. The metric can be written:

ds^{2}=c^{2}dt^{2}-a^{2}(t)dx^{2}

Where a(t) is the scale factor of the Universe at time t, and c is the speed of light.

The special characteristic of the trajectory followed by light is that ds^{2}=0 (the speed of light is ALWAYS the speed of light) along the path, which implies that \left | dx \right |=\frac{cdt}{a(t)}, or, for what I'm workin' with here (a finite time interval) \int \left | dx \right |=\int_{t_{emitted}}^{t_{now}}\frac{cdt}{a(t)}

The left side of the above equation gives thedistance light travels across the distance in STATIC space between the time of emission, and now. Obviously, to make this fit with the current view of the expanding Universe you gotta rescale the formula. Doing this gives,

a(t_{now})\int_{t_{emitted}}^{t_{now}}\frac{cdt}{a(t)}

When calculating the distance traveled in an expanding Universe we see that each segment of the lights trajectory is multiplied bythefactor \frac{a(t_{now})}{a(t)}, which is the amount by which that segment has stretched, since the moment light traversed it, until today.

So, yeah, you can calculate distance.

Anonymous 06/21/12(Thu)20:35 No.2742505

Do what everyone else does:

1. Read every Shakespeare play 2. Find a line that sorta

[Anonymous No.2742510]

The Sad Ballad of Jimmy Rustle

[Anonymous No.2742526]

Gold-Hatted Hodor

[Anonymous No.2742530]

what the fuck is going on