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/jp/ - Otaku Culture


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File: 38 KB, 805x547, cirno_math.jpg [View same] [iqdb] [saucenao] [google]
7059090 No.7059090 [Reply] [Original]

You should solve this, Cirno needs your help.

>> No.7059096

3

>> No.7059098

The answer is 9.

>> No.7059112
File: 285 KB, 684x748, gtfo.jpg [View same] [iqdb] [saucenao] [google]
7059112

Ich muss mich schon irl mit mathe 2 rumärgern, da brauch ich den scheiss net auch noch auf /jp/

>> No.7059121

~11

>> No.7059130

Cat

>> No.7059139

>>7059130
XD

>> No.7059143

11.

>> No.7059157

136-140 m2
plus minus

>> No.7059158
File: 548 KB, 800x900, 1253924478001.png [View same] [iqdb] [saucenao] [google]
7059158

>>7059121
You don't need a numerical method for this.

>> No.7059168
File: 141 KB, 500x500, 1299079564647.png [View same] [iqdb] [saucenao] [google]
7059168

>>7059130

>> No.7059180

>>7059112
I already have to deal with Germans in real life, I don't need this shit on /jp/ as well.

>> No.7059206

What are we solving?

You should state a question.

I'm not psychic, why should I solve for m when no one has asked me too?

>> No.7059221

The pleasure of being cummed inside.

>> No.7059228

Homework threads go in /sci/

>> No.7059230
File: 35 KB, 423x500, 1298848848435.jpg [View same] [iqdb] [saucenao] [google]
7059230

>>7059206
Isn't the question pretty obvious?

>> No.7059233

>>7059230
You can't be obvious with math or science.

It makes mathmeticians and scientist get all riled up.

>> No.7059234

拾壱平方㍍

>> No.7059240

You dont know if they're perfect squares, therefore you cant solve it.

>> No.7059242
File: 176 KB, 460x1380, CirnoMarisa_IdiotClothes.jpg [View same] [iqdb] [saucenao] [google]
7059242

>> No.7059243

>>7059090
Needs more information. How can I be sure that those are squares at first?

>> No.7059246

desu

>> No.7059262

>>7059240
They are squares.

>> No.7059265

are we supposed to be counting the pixels

>> No.7059273

>>7059262
Why is the 74m^2 "square" bigger than the 116m^2 "square"

>> No.7059281

>>7059273
Plenty of problems were like that in my high school. They were pretty much just there to throw you off.
However they also had right angle marks in the corners of squares.

>> No.7059285
File: 47 KB, 366x464, yui_hm.jpg [View same] [iqdb] [saucenao] [google]
7059285

>>7059273
Magic squares?

>> No.7059298
File: 207 KB, 600x717, チルノ.jpg [View same] [iqdb] [saucenao] [google]
7059298

>>7059273
non-Euclidean space.

>> No.7059302

>>7059143
/thread

>> No.7059321

http://www.wolframalpha.com/input/?i=sqrt%2819.32*%2819.32-19.26%29*%2819.32-8.6%29*%2819.32-10.77%2
9%29

10.31
To 2 decimal places. Is that method correct? I forget all this shit.

>> No.7059331

What is this, ninth grade?
Was that the joke?

Use cosine rule to determine any angle and then multiply that by 1/2 times the adjacent sides.

>> No.7059348

I have no idea what's even being asked here! All I see are a few squares with numbers!

>> No.7059368

THE ANSWER IS THE STRONGEST.

>> No.7059384

>>7059321
I don't know how you get this formula, but the correct answer should be 11. Could be right if you better approximated roots.

>> No.7059622

>>7059348
He's asking for the surface area size of the blue shaded triangle. You learned how to do it in high school. I've long since forgot how to though...

>> No.7059651
File: 21 KB, 539x319, tewi.jpg [View same] [iqdb] [saucenao] [google]
7059651

tewi.

>> No.7059654

There is a reason why I'm a Law student. Well, two, actually. To fuck math/geometry/chemistry, and to save my ass when the pedo hunters come after me.

>> No.7059661

>>7059651
sin(1/carrot)

>> No.7059668

>>7059661
arcsin(1/carrot)

>> No.7059677

>>7059668
You know what I meant.

>> No.7059689 [DELETED] 
File: 72 KB, 800x800, 1279131789488.jpg [View same] [iqdb] [saucenao] [google]
7059689

>>7059677

>> No.7059699
File: 103 KB, 480x640, 1270021324318.jpg [View same] [iqdb] [saucenao] [google]
7059699

>>7059677
yeah yeah

>> No.7059745
File: 165 KB, 482x482, i dont get it.jpg [View same] [iqdb] [saucenao] [google]
7059745

>>7059677

>> No.7059757

x^2 = 116
y^2 = 74
z^2 = 370
x = 10.77
y = 8.6
z = 19.23
cut triangle into a 90* triangle
cos-1(y/z) = degree
= 63 degrees
sin(63) = height / y
y*sin = height
height = 7.69
base * height * 1/2 = 73.9m^2

I might be wrong.

>> No.7060027
File: 158 KB, 905x1291, becauseican.png [View same] [iqdb] [saucenao] [google]
7060027

Hope this helps Cirno.

WolframAlpha Links:
http://www.wolframalpha.com/input/?i=sqrt((sqrt(370)+%2B+sqrt(116)+%2B+sqrt(74))/2*((sqrt(370)+%2B+s
qrt(116)+%2B+sqrt(74))/2-sqrt(74))*((sqrt(370)+%2B+sqrt(116)+%2B+sqrt(74))/2-sqrt(116))*((sqrt(370)+
%2B+sqrt(116)+%2B+sqrt(74))/2-sqrt(370))

http://www.wolframalpha.com/input/?i=1/2+*+sqrt{370}+*+sqrt{116}+*+sin(+arcos(+(-74%2B116%2B370)/(2+
*+sqrt(116)+sqrt(370))))

>> No.7060051
File: 26 KB, 640x360, 1249751297001.jpg [View same] [iqdb] [saucenao] [google]
7060051

>>7060027
I've never seen so much roots in my life.

>> No.7060084

>>7060027
>A¹=11
>>7059143
How did he even?

>> No.7060184

Is this a serious question?

>> No.7060210

I forgot how to math.

Seriously.

>> No.7060249
File: 205 KB, 700x962, 1249506513001.jpg [View same] [iqdb] [saucenao] [google]
7060249

>>7060184
It's serious! With the answer of this I may perceive whatever holds the world together in its inmost folds!

>> No.7060290

>>7059622
>You learned how to do it in high school.

Yeeaahh, about that...

>> No.7060321

>>7060051
You dropped of before high school?

>> No.7060327

>>7060321
I did.
Is that a bad thing?

>> No.7060331

>>7060327
define "bad"

>> No.7060336

>>7060331
I can't.

>> No.7060340

>>7060321
Yes.

>> No.7060355
File: 76 KB, 601x881, jpprof.jpg [View same] [iqdb] [saucenao] [google]
7060355

>>7060321
>implying a highschooler could solve nested roots
You need quite a bit more knowledge to simplify rootmonsters.

>> No.7060362
File: 60 KB, 200x200, getoutofmacro.png [View same] [iqdb] [saucenao] [google]
7060362

>>7060355
>implying
>jpprof.jpg

>> No.7060365

>>7060355
When I look at >>7060027 I see only stuff I learned in highschool or earlier
I couldn't solve the equation myself of course, since I didn't remember all of the formulas and I'm too lazy to just check them in a math book.

>> No.7060370

Alright Cirno, follow along:
Let s = (√ (74)+√ (116)+√ (370))/2

Next, we can find the area with:
A = √ (s(s-√ (74))(s-√ (116))(s-√ (370)))

I'll let solving that be an exercise to you Cirno.

>> No.7060371

>>7060355
They teach cosine and sine law in High school.

>> No.7060380

>>7060365
I have a program on my calculator I wrote to solve triangles quickly.
It's the only way I remember some of these formulas.

>> No.7060397
File: 44 KB, 598x545, Capture.png [View same] [iqdb] [saucenao] [google]
7060397

>>7060370
as such

>> No.7060402

>>7060380
How does it work? Is it available for download?

>> No.7060410

>>7060371
They didn't when I was in high school, about 5 years ago. Even in precal (the highest math I took in high school) we were told to ignore trig functions until college. Then again, Texas isn't known for it's QUALITY primary education system, so there are probably higher standards wherever you went to school.

>> No.7060411

Why did /jp/ help this guy with his geometry homework?

>> No.7060413

>>7060397
no, it isn't exactly 11, it's like 11.01434523 or something. try again son, eventually you'll get it

>> No.7060416

>>7060411
Why not? It's a challange.

>> No.7060430

>>7060370
>A = √ (s(s-√ (74))(s-√ (116))(s-√ (370)))
How do you get this formula?
I tried to derivate it with "Area=1/2*lengh*highs" and Pythagoras' theorem, less successfull.

>> No.7060433

>>7060411
Because Cirno asked. How could I say no to Cirno?

>> No.7060447

>>7060430
That's Heron's formula.

>"Area=1/2*lengh*highs"
You don't have the height.

>Pythagoras' theorem
1 - It isn't a right triangle.
2 - What the fuck, I want the area, not the length of side c.

Oh wow, I thought that this was a challenge, but it's like I'm really helping some underageb& with his homework....

>> No.7060449

1.Find sides. (sqrt(area));
2.Plug sides into equation:
x^2=a^2+b^2-2ab(Cos(angle X)); Find angle X.
3. use angle X and sine law to find the height.
4. Area = (1/2)(base*height);
5. babby's first math course.

>> No.7060463

>do my math homework for me

No, OP. Fuck off.

>> No.7060465

>>7060371
>>7060365
I meant the rot-monster in the middle, not cosine law or anything. If you have seen such a term in high-school, you probably just put some numbers into your calculator, but that's not even interesting, it's just approximating a possible solution.

>> No.7060472

>>7060430
It's not based on half-times-height-times-base, it's just another formula for finding out the area of a triangle, if you've got all three sides.
A = √ (s(s-a)(s-b)(s-c))
where s = (a+b+c)/2
and a, b, c are of course the sides of the triangle.

>> No.7060484
File: 24 KB, 240x400, 1269601171003.jpg [View same] [iqdb] [saucenao] [google]
7060484

>>7060447
protip: you can split every triangle into two right triangles. pythagoras theorem is the only thing you need here. searching on google for some formulas you don't even derivate yourself is just boring and silly.

>> No.7060487

Just take the square root of all squares to find the lengths of the sides, and use Heron's formula. Done. This is high school stuff for fuck's sakes. /r/ a ban for OP for being underage.

>> No.7060491

>>7060465
I don't mind roots. They look intimating in radical form, but it looks a lot nicer when you make them fractional exponents. They are more time consuming than anything, not hard, like adding long rows of numbers in second grade was.

>> No.7060505

>>7060484
>protip: you can split every triangle into two right triangles.
But why? Just use the information given. The more steps you take to get to a solution, the more potential errors you introduce.

> searching on google for some formulas you don't even derivate yourself is just boring and silly.
You should never need to 'derivate' something as simple as Heron's formula.

>> No.7060506

>>7060465
Eh, don't worry, you only have to deal with such monstrosities in school. If you get a job that actually requires you to deal with them, you just use a proper calculator, like a normal person.

>> No.7060507

/jp/ - Doing your homework if you will add Cirno to it.


OP should do his homework himself and get ignored for being 2nd grade of middle school.

>> No.7060508

>>7060402
Erm, I just wrote it using my rudimentary-at-best knowledge of the TI-BASIC language.
No idea how to upload it. Lost my cables a long time ago.
All it does is punch the numbers into the formulas anyway.

>> No.7060514

>>7060484
Unless you have the angles, you can't make assumptions of what the length of the split side will be.

This thread is retarded anyway, it has nothing to do with /jp/ and it's just a kid wanting help with his math homework. Go ask /sci/, they love helping kids do their homework.

>> No.7060526

>>7060508
You can just upload it to mediafire for free.
I'm curious how it works, but if it's too much of a bother to you, I'll live.

>> No.7060531

>>7060463
You are ~70 posts too late for that shit.

>> No.7060535

>>7060514
read >>7060027
You CAN solve it that way. But to tell the truth, Heron's formula is probably better here.

>> No.7060540

>>7060514
If you really wanted to be retarded you could get the angles with the law of cosine.

a² = b²+c² -2bc(cosA)
c² = a²+c² -2ac(cosB)
c² = a²+b² -2ab(cosC)

Which leads too:
arccos((a²-b²-c²)/-2bc)=A
arccos((b²-a²-c²)/-2ac)=B
arccos((c²-a²-c²)/-2ab)=C

>> No.7060548

>>7060526
I think he means that he doesn't have the cables needed to get it off of the calculator anymore. (And if it is TI, the drivers won't work with x64 anyway, because TI is too fucking cheap to have them signed.)

>> No.7060553

>>7060526
It's pretty damn long to type by hand since it basically does each different method separately.
I'm grabbing the TI-connect software so I can get it as a .txt file.

>> No.7060561

>>7060505
>The more steps you take to get to a solution, the more potential errors you introduce.
Well, if you don't know about a formula that can solve this problem directly you have to derivate one from the things you know. And that is in my case pythagoras and the simple area-formula Area=1/2*b*h.

>> No.7060562

>YFW you realize the answer was given 5 minutes after OP

>>7059121

>> No.7060565

>>7060553
>it basically does each different method separately.
Ah, I see. That's the thing that interested me most, I thought you input what data you have, and it tries to find out the best way to solve it or something.

>> No.7060566

>>7060561
>derivate

You mean "derive".

>> No.7060570

>>7060548
>the drivers won't work with x64 anyway
You're shitting me.

>> No.7060580
File: 29 KB, 419x378, TrigComp.jpg [View same] [iqdb] [saucenao] [google]
7060580

>>7060565
Well, you pick which method to use (SSA, ASA, whatever) and it uses that.

>> No.7060585

>>7060570
Won't work for me on my 2yo TI-89, I doubt they released updated drivers for any other model either.

>> No.7060589

>>7060561
>Well, if you don't know about a formula that can solve this problem directly you have to derivate one from the things you know.
Or you can find the formula that solves the problem directly. Just you can write with a piece of charcoal you found somewhere, or you can find a pencil. You can do it, true, but why bother when there is an easier solution?

>> No.7060595

>>7060566
I think he wants to take the derivative actually. Not sure how that helps him find the area though.

>> No.7060600

>>7060580
I see. Seems much more possible than I thought now. Still, impressive.

>> No.7060607

>>7060580
Can that solve for the ambiguous case (SSA where two triangles can be formed) too?

>> No.7060617

>>7060607
That's a very good question, and I don't think I thought about that when I made the program.

>> No.7060618
File: 40 KB, 428x383, 1249848235001.png [View same] [iqdb] [saucenao] [google]
7060618

>>7060514
You don't need angles, just simple propositions from elemental number theory and pythagoras theorem. You can take the blue-triangle from the puzzle, add two right triangle and add a rectangle to create a big right triangle, furthermore:
5²+7²=74
4²+10²=116
I hope, you get it.

>> No.7060626 [DELETED] 

>>7060617
Sure enough, I get a DOMAIN error.
Sonuvabitch.

>> No.7060654

let A=1=B
A²=B² because A=B, so
A²=AB and
A²-B²=A²-AB , next we factor
(A+B)(A-B)=A(A-B) , divide like terms
(A+B)=A
substituting our variables for their values we learn that
2=1.

>> No.7060667
File: 157 KB, 500x600, 1249827158001.jpg [View same] [iqdb] [saucenao] [google]
7060667

>>7060654
Dividing by zero, only gods can do this.

>> No.7060685

>>7060654
If A and B both equal one then (A-B) equals 0.
So in (A+B)(A-B)=A(A-B), you divide both sides by zero.
And you don't divide by zero.

>> No.7060698

The answer is root of 74,116,370. Jesus christ are you all in fucking middle school? The squares all say m^2 . That means the squares are all perfect squares. Take the square root to get the length of a single side and find the length of every side of the triangle.

>> No.7060701
File: 92 KB, 1096x682, Mathematical_fallacy.jpg [View same] [iqdb] [saucenao] [google]
7060701

>>7060654

>> No.7060710

>>7060698
The dimensions of my prison cell are 8ft by 6ft. That means that the area of the floor is 48ft². By your logic, my cell is a perfect square, as is 48.

>> No.7060712

>>7060701
WIKIPEDIA STOLE MY PROOF!

>> No.7060718

>>7060710
Dude, how did you get in prison?

>> No.7060749

>>7060718
I broke the Law of Cosine.

>> No.7060772
File: 193 KB, 419x481, 1249791039001.png [View same] [iqdb] [saucenao] [google]
7060772

>>7060718
Haaaaaaaaai, i know the answer! I know it! He stole my sweets.
>>7060749
Hahaha, i understand the joke!

>> No.7060786

>>7060772
Get the fuck out of here and take OP with you.

>> No.7060814

>>7060749
I wanted to personally thank you for this post.
That is all.

>> No.7060828

>>7060821
It isn't. It's unrelated. Filling it with faggotry like that only makes things worse.

>> No.7060821
File: 749 KB, 1343x1356, 1264203073001.jpg [View same] [iqdb] [saucenao] [google]
7060821

>>7060786
Helping other people doing math is the best way to learn or relearn it yourself! It's fun!

>> No.7060832
File: 27 KB, 300x400, billy.jpg [View same] [iqdb] [saucenao] [google]
7060832

>>7060828
What about now?

>> No.7060856

what the fuck I went to a math and science school and was never taught this heron's formula. I remember solving problems like this before but it was alwas using laws of sines and cosines.

>> No.7060864

you are still discussing this? c'mon

>> No.7060904

Are you kidding? That problem is so trivial. Assuming those are squares, we can proceed and use Heron's Formula. Once we find the semi-perimeter, we can use that find the area.

s = (√74+√116+√370)/2 = 19.30401947 units

A = √((s)(s-√74)(s-√116)(s-√370)) = 11 sq. units

>>7060430

lol, gb2MathTeam

>> No.7060948

>>7060856
Well, i never heard it too.

>> No.7060963

>>7060856
Its an obscure formula only used for these types of problems.

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