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/diy/ - Do It Yourself

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>> No.1627273 [View]
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1627273

>>1627268
I can't honestly say. I'm playing with diode clippers.

I see when the breakdown voltage is reached, the diode begins to conduct and thus shunts the current away from Vout. That's also where the waveform of the triangle wave begins to distort.

I'm trying to develop intuition for this. The way I'm thinking of it now is that in order to drive that current through the diode it must "spend" some voltage to do so. So some of the output voltage is redirected towards making the diode conduct, thus depressing the output voltage and distorting the waveform in the process.

Granted, that "spending of voltage" might just be from the voltage required to make the diode conduct and not be an inherent relationship between current and voltage.

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