/diy/ - Do It Yourself

>>1945201
dE is the added energy over that tiny timeframe dt. 10V and 1A makes 10W, 10W over 1µs is 10µJ. The energy after that 1µs (say N=151), E(t+dt) = E(151µs) is going to be 10µJ higher than it was before (N=150), E(t) = E(150µs). The accumulated energy is the sum of each step.