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>> No.1448022 [View]
File: 5 KB, 507x255, 00069.png [View same] [iqdb] [saucenao] [google]
1448022

>>1448016
lastly, i have a question about something that'll probably never be relevant in my life, but that intrigued me. it's about something said on this page: https://www.allaboutcircuits.com/textbook/direct-current/chpt-3/common-sources-hazard/

they say this about pic related:
>If the distance between the two ground contact points (the downed cable and the system ground) is small, there will be substantial voltage dropped along short distances between the two points. Therefore, a person standing on the ground between those two points will be in danger of receiving an electric shock by intercepting a voltage between their two feet!

>One practical precaution a person could take if they see a power line falling towards the ground is to only contact the ground at one point, either by running away (when you run, only one foot contacts the ground at any given time), or if there’s nowhere to run, by standing on one foot.

what I don't get is why you'd be shocked standing on both feet. you would be grounded, so would the voltage between your body and any point on the ground be 0v? why would the current suddenly change its path to go through your legs? I understand that a human body is probably less resistive than the ground, so current would prefer the legs, but how can they be "pushed" through your legs if there's nothing pushing them (thinking of volts as the pressure of water in the water flow/electricity analogy)? this, however, conflicts with what I "know" about current going to infinity when the voltage is 0. also, why would standing on one leg make you safe? why wouldn't the electricity simply go through the base of your foot?

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