/biz/ - Business & Finance

[Anonymous No.24314650]

If you guys are such business and finance geniuses, can you also solve this??

[Anonymous No.24314673]

Something about hcos

[Anonymous No.24314679]

112

[Anonymous No.24314702]

>>24314650
Remind me what's the formula for a parabola without looking it up?

[Anonymous No.24314708]

>implying you’re a genius for being able to do basic calculus

[Anonymous No.24314766]

>>24314702
I know I'm posting in a troll thread, but a suspension cable is not a parabola. It's a hyperbolic function like cosh or something.

[Anonymous No.24314767]

I used a ruler, the answer is 83.3333m

[Anonymous No.24314776]

0 m

[Anonymous No.24314780]

>the poles are 50m tall

[Anonymous No.24314787]

>>24314650
Probably some meme like 0 meters

[Anonymous No.24314797]

>>24314650
Replace the 20 with 10 and vwallah
https://mindyourdecisions.com/blog/2018/07/12/can-you-solve-amazons-hanging-cable-interview-question/

[Anonymous No.24314813]

>>24314780
It didn't say drawn to scale you monkey

Its just a visual explanation

[Anonymous No.24314831]

the cable has to go down 40 meters and back up 40 meters but its 80 meters long, the answer is it goes down and up vertically

[Anonymous No.24314834]

>>24314650
0, ez.

[Anonymous No.24314856]

>>24314650
40m

[Anonymous No.24314882]

>>24314650
However long that was most cost efficient for the business that’s using it.

[Anonymous No.24314885]

>>24314831
your mom goes down and up vertically on my pole

[Anonymous No.24314903]

32m

[Anonymous No.24314910]

>>24314650
0

[Anonymous No.24314947]

I don't see any advantage of making money out of this, so I don't care.

[Anonymous No.24314978]

>>24314766
Maybe you're right, maybe not, I don't care enough but eventually I will. First I want to make it.
https://www.onlinemath4all.com/word-problems-involving-parabola-and-hyperbola.html

[Anonymous No.24315035]

>>24314978
it doesnt matter what the function is, an 80m cable can only go 80 meters in the vertical + horizontal directions, because you have the vertical distance the cable runs 2x40m you can easily get the horizontal is 0

[Anonymous No.24315042]

>>24314766
catenary to be exact

[Anonymous No.24315120]

>>24314766
I want to correct myself: The problem is not a troll in that there actually is one, correct answer (the picture just makes it misleading at first glance, making me think it was a troll).

[Anonymous No.24315172]

>>24314776
>>24314787
Shit, le trick question, should have expected it.

[Anonymous No.24315290]

>>24315035
Yes, thanks. I got tricked, fuck Jeff.

[Anonymous No.24315308]

>>24314813

[Anonymous No.24315819]

>>24314650
Clearly it's 0 if you aren't retarded.
The drawing is just trying to confuse the autists.

[Anonymous No.24315964]

>>24314650
I'll pay a nerd to do the math.

[Anonymous No.24316103]

The question is bologna because
>>24314780
The poles can't be 50m tall if the cable is 80m long meeting 10m above the ground in the middle between the two poles. That would be 40m length of cable on either side. 50m height of the pole minus the 10m height of means that the height from top to bottom of the cable would be 40m. Taking the top 40m of the the pole and running to the lowest point of the cable forms a right triangle. The side of the triangle formed would have to exceed 40m in order for it to be a triangle in the first place, yet here we are with 40m being the length of the relevant segment of cable. It's even more bologna when you consider the bend in the cable.

[Anonymous No.24316122]

have a degree in math, i barely remember hearing about catenary equations. did a quick approximation with pythagorean theorem and i suspected this was another dumb kike trick question, and the video solution confirms this.

[Anonymous No.24316169]

>>24314650
You're moms gey

[Anonymous No.24316237]

>>24316103
tl;dr the poles would have to occupy the exact same space and the cable would also have to travel through that exact same space and bend at a 360 degree angle in order for this problem to be "real" with an answer of 0m

[Anonymous No.24316253]

>>24314650
Good for you if you can solve this question anon. Now tell me how much is your net worth and how much pussy you get with that little thing ?
topfuckingkek at this miserable fuck thinking about useless math questions

[Anonymous No.24316397]

>>24316253
>Now tell me how much is your net worth
80k
>how much pussy you get
0

[Anonymous No.24316402]

>>24316237
>poles would have to occupy the exact same space
No, there would just be 0 distance between them. Of course the there wouldn't be room for a rope anyway.
P00p p00p p33 hahaha imgayimgayimgay

[Anonymous No.24316429]

>>24316397
around 200k nigger

[Anonymous No.24316580]

>>24314947
But you wasted your time replying.

[Anonymous No.24316594]

I am thinking:
50 * X = Integral df(x) + inverse Integral df(x)
Then just solve for X.
(Perhaps inverse Integral isn't a thing, but I mean the integral which gets the area above the line.)

Don't know how to define f(x) though, but shouldn't you be able to do that here?

[Anonymous No.24316636]

>>24314650
the real question was the friends we made along the way?

[Anonymous No.24316659]

>>24314650
The question didn't ask for an answer in any particular unit. I chose to answer in a unit of my own creation, one of which is equal to the distance between the two poles. Therefore, the answer in my unit is 1.

[Anonymous No.24316777]

>>24314650
40 m

[Anonymous No.24316809]

>>24316777
plotted y=x^2/6.4-5x+50 parabola that matched the cable

[Anonymous No.24316825]

>>24314650
The answer is 0.

[Anonymous No.24316976]

>>24314650
the picture is designed to throw you off. its a lie. the poles are 0 m apart.

[Anonymous No.24316981]

>>24316777
now measure the relevant length of that and tell us its 80m

[Anonymous No.24317015]

>>24316981
ya nvm its 0

[Anonymous No.24317065]

>>24314650
80m, distance doesnt change when it bends

[Anonymous No.24317093]

>>24314650
0. The meters aren't at any distance and the cable is falling straight down.

[Anonymous No.24317096]

It equals to 40*tan(1 rad)=62.296 m

you're welcome. I also hold Statera.

[Anonymous No.24317255]

>>24314650
Around 0 I think.
If we make an approximate triangle for one half, the one side is 40 and the hypotenuse is 40. According to Pythagoras, the length of the bottom half is around 0.

[Anonymous No.24317584]

>>24314910
0 is correct, cut the cable in half to easily imagine why.

[Anonymous No.24317961]

>>24314650
Hmm. I got 17 bros